3b=8-(b-8)

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Solution for 3b=8-(b-8) equation: 



3b=8-(b-8)

We move all terms to the left:

3b-(8-(b-8))=0



We calculate terms in parentheses: -(8-(b-8)), so:

8-(b-8)

determiningTheFunctionDomain
-(b-8)+8

We get rid of parentheses

-b+8+8

We add all the numbers together, and all the variables

-1b+16

Back to the equation:

-(-1b+16)



We get rid of parentheses

3b+1b-16=0

We add all the numbers together, and all the variables

4b-16=0

We move all terms containing b to the left, all other terms to the right

4b=16

b=16/4

b=4

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