3b=4(b+3)

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Solution for 3b=4(b+3) equation: 



3b=4(b+3)

We move all terms to the left:

3b-(4(b+3))=0



We calculate terms in parentheses: -(4(b+3)), so:

4(b+3)

We multiply parentheses

4b+12

Back to the equation:

-(4b+12)



We get rid of parentheses

3b-4b-12=0

We add all the numbers together, and all the variables

-1b-12=0

We move all terms containing b to the left, all other terms to the right

-b=12

b=12/-1

b=-12

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