3b/2+b+90+(2b-90)+(b+45)=540

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Solution for 3b/2+b+90+(2b-90)+(b+45)=540 equation: 



3b/2+b+90+(2b-90)+(b+45)=540

We move all terms to the left:

3b/2+b+90+(2b-90)+(b+45)-(540)=0

We add all the numbers together, and all the variables

b+3b/2+(2b-90)+(b+45)-450=0

We get rid of parentheses

b+3b/2+2b+b-90+45-450=0

We multiply all the terms by the denominator


b*2+3b+2b*2+b*2-90*2+45*2-450*2=0

We add all the numbers together, and all the variables

3b+b*2+2b*2+b*2-990=0

Wy multiply elements

3b+2b+4b+2b-990=0

We add all the numbers together, and all the variables

11b-990=0

We move all terms containing b to the left, all other terms to the right

11b=990

b=990/11

b=90

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