3b/12-(8b-12/12)=36

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Solution for 3b/12-(8b-12/12)=36 equation: 



3b/12-(8b-12/12)=36

We move all terms to the left:

3b/12-(8b-12/12)-(36)=0

We add all the numbers together, and all the variables

3b/12-(8b-1)-36=0

We get rid of parentheses

3b/12-8b+1-36=0

We multiply all the terms by the denominator


3b-8b*12+1*12-36*12=0

We add all the numbers together, and all the variables

3b-8b*12-420=0

Wy multiply elements

3b-96b-420=0

We add all the numbers together, and all the variables

-93b-420=0

We move all terms containing b to the left, all other terms to the right

-93b=420

b=420/-93

b=-4+16/31

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