3b/(b-4)=3/7

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Solution for 3b/(b-4)=3/7 equation: 


D( b )

b-4 = 0

b-4 = 0

b-4 = 0

b-4 = 0 // + 4

b = 4

b in (-oo:4) U (4:+oo)

(3*b)/(b-4) = 3/7 // - 3/7

(3*b)/(b-4)-(3/7) = 0

(3*b)/(b-4)-3/7 = 0

(3*7*b)/(7*(b-4))+(-3*(b-4))/(7*(b-4)) = 0

3*7*b-3*(b-4) = 0

18*b+12 = 0

(18*b+12)/(7*(b-4)) = 0

(18*b+12)/(7*(b-4)) = 0 // * 7*(b-4)

18*b+12 = 0

18*b+12 = 0 // - 12

18*b = -12 // : 18

b = -12/18

b = -2/3

b = -2/3

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