3b-8=10-2(4-4b)

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Solution for 3b-8=10-2(4-4b) equation: 



3b-8=10-2(4-4b)

We move all terms to the left:

3b-8-(10-2(4-4b))=0

We add all the numbers together, and all the variables

3b-(10-2(-4b+4))-8=0



We calculate terms in parentheses: -(10-2(-4b+4)), so:

10-2(-4b+4)

determiningTheFunctionDomain
-2(-4b+4)+10

We multiply parentheses

8b-8+10

We add all the numbers together, and all the variables

8b+2

Back to the equation:

-(8b+2)



We get rid of parentheses

3b-8b-2-8=0

We add all the numbers together, and all the variables

-5b-10=0

We move all terms containing b to the left, all other terms to the right

-5b=10

b=10/-5

b=-2

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