3b-72=b+58

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Solution for 3b-72=b+58 equation: 



3b-72=b+58

We move all terms to the left:

3b-72-(b+58)=0

We get rid of parentheses

3b-b-58-72=0

We add all the numbers together, and all the variables

2b-130=0

We move all terms containing b to the left, all other terms to the right

2b=130

b=130/2

b=65

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