3b-2(b-5)=3(2b-15)

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Solution for 3b-2(b-5)=3(2b-15) equation: 


Simplifying
3b + -2(b + -5) = 3(2b + -15)

Reorder the terms:
3b + -2(-5 + b) = 3(2b + -15)
3b + (-5 * -2 + b * -2) = 3(2b + -15)
3b + (10 + -2b) = 3(2b + -15)

Reorder the terms:
10 + 3b + -2b = 3(2b + -15)

Combine like terms: 3b + -2b = 1b
10 + 1b = 3(2b + -15)

Reorder the terms:
10 + 1b = 3(-15 + 2b)
10 + 1b = (-15 * 3 + 2b * 3)
10 + 1b = (-45 + 6b)

Solving
10 + 1b = -45 + 6b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-6b' to each side of the equation.
10 + 1b + -6b = -45 + 6b + -6b

Combine like terms: 1b + -6b = -5b
10 + -5b = -45 + 6b + -6b

Combine like terms: 6b + -6b = 0
10 + -5b = -45 + 0
10 + -5b = -45

Add '-10' to each side of the equation.
10 + -10 + -5b = -45 + -10

Combine like terms: 10 + -10 = 0
0 + -5b = -45 + -10
-5b = -45 + -10

Combine like terms: -45 + -10 = -55
-5b = -55

Divide each side by '-5'.
b = 11

Simplifying
b = 11

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