3b-2(b+1)-b=8(b-1)-8b

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Solution for 3b-2(b+1)-b=8(b-1)-8b equation: 


Simplifying
3b + -2(b + 1) + -1b = 8(b + -1) + -8b

Reorder the terms:
3b + -2(1 + b) + -1b = 8(b + -1) + -8b
3b + (1 * -2 + b * -2) + -1b = 8(b + -1) + -8b
3b + (-2 + -2b) + -1b = 8(b + -1) + -8b

Reorder the terms:
-2 + 3b + -2b + -1b = 8(b + -1) + -8b

Combine like terms: 3b + -2b = 1b
-2 + 1b + -1b = 8(b + -1) + -8b

Combine like terms: 1b + -1b = 0
-2 + 0 = 8(b + -1) + -8b
-2 = 8(b + -1) + -8b

Reorder the terms:
-2 = 8(-1 + b) + -8b
-2 = (-1 * 8 + b * 8) + -8b
-2 = (-8 + 8b) + -8b

Combine like terms: 8b + -8b = 0
-2 = -8 + 0
-2 = -8

Solving
-2 = -8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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