3b-(b/3)-4=(b/4)-3b+4

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Solution for 3b-(b/3)-4=(b/4)-3b+4 equation: 


b in (-oo:+oo)

3*b-(b/3)-4 = b/4-(3*b)+4 // - b/4-(3*b)+4

3*b-(b/3)-(b/4)+3*b-4-4 = 0

65/12*b-8 = 0 // + 8

65/12*b = 8 // : 65/12

b = 8/65/12

b = 96/65

b = 96/65

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