3b+8+2(b-4)=70

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Solution for 3b+8+2(b-4)=70 equation: 



3b+8+2(b-4)=70

We move all terms to the left:

3b+8+2(b-4)-(70)=0

We add all the numbers together, and all the variables

3b+2(b-4)-62=0

We multiply parentheses

3b+2b-8-62=0

We add all the numbers together, and all the variables

5b-70=0

We move all terms containing b to the left, all other terms to the right

5b=70

b=70/5

b=14

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