3b+3(1-2b)=6

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Solution for 3b+3(1-2b)=6 equation: 



3b+3(1-2b)=6

We move all terms to the left:

3b+3(1-2b)-(6)=0

We add all the numbers together, and all the variables

3b+3(-2b+1)-6=0

We multiply parentheses

3b-6b+3-6=0

We add all the numbers together, and all the variables

-3b-3=0

We move all terms containing b to the left, all other terms to the right

-3b=3

b=3/-3

b=-1

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