3b*3b-7=68

Solution for 3b*3b-7=68 equation:

3b*3b-7=68

We move all terms to the left:

3b*3b-7-(68)=0

We add all the numbers together, and all the variables

3b*3b-75=0

Wy multiply elements

9b^2-75=0

a = 9; b = 0; c = -75;
Δ = b2-4ac
Δ = 02-4·9·(-75)
Δ = 2700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2700}=\sqrt{900*3}=\sqrt{900}*\sqrt{3}=30\sqrt{3}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{3}}{2*9}=\frac{0-30\sqrt{3}}{18}
=-\frac{30\sqrt{3}}{18}
=-\frac{5\sqrt{3}}{3}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{3}}{2*9}=\frac{0+30\sqrt{3}}{18}
=\frac{30\sqrt{3}}{18}
=\frac{5\sqrt{3}}{3}
$