3a-8=3(a+1)+11a+1

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Solution for 3a-8=3(a+1)+11a+1 equation:



3a-8=3(a+1)+11a+1
We move all terms to the left:
3a-8-(3(a+1)+11a+1)=0
We calculate terms in parentheses: -(3(a+1)+11a+1), so:
3(a+1)+11a+1
We add all the numbers together, and all the variables
11a+3(a+1)+1
We multiply parentheses
11a+3a+3+1
We add all the numbers together, and all the variables
14a+4
Back to the equation:
-(14a+4)
We get rid of parentheses
3a-14a-4-8=0
We add all the numbers together, and all the variables
-11a-12=0
We move all terms containing a to the left, all other terms to the right
-11a=12
a=12/-11
a=-1+1/11

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