3a-5=(5a+1)+10a+3

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Solution for 3a-5=(5a+1)+10a+3 equation: 



3a-5=(5a+1)+10a+3

We move all terms to the left:

3a-5-((5a+1)+10a+3)=0



We calculate terms in parentheses: -((5a+1)+10a+3), so:

(5a+1)+10a+3

We add all the numbers together, and all the variables

10a+(5a+1)+3

We get rid of parentheses

10a+5a+1+3

We add all the numbers together, and all the variables

15a+4

Back to the equation:

-(15a+4)



We get rid of parentheses

3a-15a-4-5=0

We add all the numbers together, and all the variables

-12a-9=0

We move all terms containing a to the left, all other terms to the right

-12a=9

a=9/-12

a=-3/4

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