3a-2(4a+9)=-8-2(-10+5a)

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Solution for 3a-2(4a+9)=-8-2(-10+5a) equation: 



3a-2(4a+9)=-8-2(-10+5a)

We move all terms to the left:

3a-2(4a+9)-(-8-2(-10+5a))=0

We add all the numbers together, and all the variables

3a-2(4a+9)-(-8-2(5a-10))=0

We multiply parentheses

3a-8a-(-8-2(5a-10))-18=0



We calculate terms in parentheses: -(-8-2(5a-10)), so:

-8-2(5a-10)

determiningTheFunctionDomain
-2(5a-10)-8

We multiply parentheses

-10a+20-8

We add all the numbers together, and all the variables

-10a+12

Back to the equation:

-(-10a+12)



We add all the numbers together, and all the variables

-5a-(-10a+12)-18=0

We get rid of parentheses

-5a+10a-12-18=0

We add all the numbers together, and all the variables

5a-30=0

We move all terms containing a to the left, all other terms to the right

5a=30

a=30/5

a=6

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