3a-2(4-4a)=7a+5

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Solution for 3a-2(4-4a)=7a+5 equation: 



3a-2(4-4a)=7a+5

We move all terms to the left:

3a-2(4-4a)-(7a+5)=0

We add all the numbers together, and all the variables

3a-2(-4a+4)-(7a+5)=0

We multiply parentheses

3a+8a-(7a+5)-8=0

We get rid of parentheses

3a+8a-7a-5-8=0

We add all the numbers together, and all the variables

4a-13=0

We move all terms containing a to the left, all other terms to the right

4a=13

a=13/4

a=3+1/4

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