3a-13=2(a+1)+16a+1

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Solution for 3a-13=2(a+1)+16a+1 equation: 



3a-13=2(a+1)+16a+1

We move all terms to the left:

3a-13-(2(a+1)+16a+1)=0



We calculate terms in parentheses: -(2(a+1)+16a+1), so:

2(a+1)+16a+1

We add all the numbers together, and all the variables

16a+2(a+1)+1

We multiply parentheses

16a+2a+2+1

We add all the numbers together, and all the variables

18a+3

Back to the equation:

-(18a+3)



We get rid of parentheses

3a-18a-3-13=0

We add all the numbers together, and all the variables

-15a-16=0

We move all terms containing a to the left, all other terms to the right

-15a=16

a=16/-15

a=-1+1/15

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