3a+5(a-20)=6(a+4)

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Solution for 3a+5(a-20)=6(a+4) equation: 



3a+5(a-20)=6(a+4)

We move all terms to the left:

3a+5(a-20)-(6(a+4))=0

We multiply parentheses

3a+5a-(6(a+4))-100=0



We calculate terms in parentheses: -(6(a+4)), so:

6(a+4)

We multiply parentheses

6a+24

Back to the equation:

-(6a+24)



We add all the numbers together, and all the variables

8a-(6a+24)-100=0

We get rid of parentheses

8a-6a-24-100=0

We add all the numbers together, and all the variables

2a-124=0

We move all terms containing a to the left, all other terms to the right

2a=124

a=124/2

a=62

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