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3a+4(5+2a)=1+11(a+2)
We move all terms to the left:
3a+4(5+2a)-(1+11(a+2))=0
We add all the numbers together, and all the variables
3a+4(2a+5)-(1+11(a+2))=0
We multiply parentheses
3a+8a-(1+11(a+2))+20=0
We calculate terms in parentheses: -(1+11(a+2)), so:We add all the numbers together, and all the variables
1+11(a+2)
determiningTheFunctionDomain 11(a+2)+1
We multiply parentheses
11a+22+1
We add all the numbers together, and all the variables
11a+23
Back to the equation:
-(11a+23)
11a-(11a+23)+20=0
We get rid of parentheses
11a-11a-23+20=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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