3a+4(3(1.45/4a)=1.35

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Solution for 3a+4(3(1.45/4a)=1.35 equation: 



3a+4(3(1.45/4a)=1.35

We move all terms to the left:

3a+4(3(1.45/4a)-(1.35)=0



Domain of the equation: 4a)-(1.35)!=0

a∈R



We add all the numbers together, and all the variables

3a+4(3(+1.45/4a)-(1.35)=0

We multiply all the terms by the denominator


3a*4a)-(1.35)+4(3(+1.45=0

Wy multiply elements

12a^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{24}=0$

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