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3a(a+7)=0
We multiply parentheses
3a^2+21a=0
a = 3; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·3·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*3}=\frac{-42}{6} =-7 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*3}=\frac{0}{6} =0 $
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