3a(a+4)-1(a+4)=2(a+4)

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Solution for 3a(a+4)-1(a+4)=2(a+4) equation:


Simplifying
3a(a + 4) + -1(a + 4) = 2(a + 4)

Reorder the terms:
3a(4 + a) + -1(a + 4) = 2(a + 4)
(4 * 3a + a * 3a) + -1(a + 4) = 2(a + 4)
(12a + 3a2) + -1(a + 4) = 2(a + 4)

Reorder the terms:
12a + 3a2 + -1(4 + a) = 2(a + 4)
12a + 3a2 + (4 * -1 + a * -1) = 2(a + 4)
12a + 3a2 + (-4 + -1a) = 2(a + 4)

Reorder the terms:
-4 + 12a + -1a + 3a2 = 2(a + 4)

Combine like terms: 12a + -1a = 11a
-4 + 11a + 3a2 = 2(a + 4)

Reorder the terms:
-4 + 11a + 3a2 = 2(4 + a)
-4 + 11a + 3a2 = (4 * 2 + a * 2)
-4 + 11a + 3a2 = (8 + 2a)

Solving
-4 + 11a + 3a2 = 8 + 2a

Solving for variable 'a'.

Reorder the terms:
-4 + -8 + 11a + -2a + 3a2 = 8 + 2a + -8 + -2a

Combine like terms: -4 + -8 = -12
-12 + 11a + -2a + 3a2 = 8 + 2a + -8 + -2a

Combine like terms: 11a + -2a = 9a
-12 + 9a + 3a2 = 8 + 2a + -8 + -2a

Reorder the terms:
-12 + 9a + 3a2 = 8 + -8 + 2a + -2a

Combine like terms: 8 + -8 = 0
-12 + 9a + 3a2 = 0 + 2a + -2a
-12 + 9a + 3a2 = 2a + -2a

Combine like terms: 2a + -2a = 0
-12 + 9a + 3a2 = 0

Factor out the Greatest Common Factor (GCF), '3'.
3(-4 + 3a + a2) = 0

Factor a trinomial.
3((-4 + -1a)(1 + -1a)) = 0

Ignore the factor 3.

Subproblem 1

Set the factor '(-4 + -1a)' equal to zero and attempt to solve: Simplifying -4 + -1a = 0 Solving -4 + -1a = 0 Move all terms containing a to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1a = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1a = 0 + 4 -1a = 0 + 4 Combine like terms: 0 + 4 = 4 -1a = 4 Divide each side by '-1'. a = -4 Simplifying a = -4

Subproblem 2

Set the factor '(1 + -1a)' equal to zero and attempt to solve: Simplifying 1 + -1a = 0 Solving 1 + -1a = 0 Move all terms containing a to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1a = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1a = 0 + -1 -1a = 0 + -1 Combine like terms: 0 + -1 = -1 -1a = -1 Divide each side by '-1'. a = 1 Simplifying a = 1

Solution

a = {-4, 1}

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