3a(7a-5)=37

Solution for 3a(7a-5)=37 equation:

3a(7a-5)=37

We move all terms to the left:

3a(7a-5)-(37)=0

We multiply parentheses

21a^2-15a-37=0

a = 21; b = -15; c = -37;
Δ = b2-4ac
Δ = -152-4·21·(-37)
Δ = 3333
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{3333}}{2*21}=\frac{15-\sqrt{3333}}{42}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{3333}}{2*21}=\frac{15+\sqrt{3333}}{42}
$