3a(4-5a)=

Solution for 3a(4-5a)= equation:

3a(4-5a)=

We move all terms to the left:

3a(4-5a)-()=0

We add all the numbers together, and all the variables

3a(-5a+4)-()=0

We add all the numbers together, and all the variables

3a(-5a+4)=0

We multiply parentheses

-15a^2+12a=0

a = -15; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-15)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-15}=\frac{-24}{-30}
=4/5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-15}=\frac{0}{-30}
=0
$