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3=x-3/4x
We move all terms to the left:
3-(x-3/4x)=0
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+x-3/4x)+3=0
We get rid of parentheses
-x+3/4x+3=0
We multiply all the terms by the denominator
-x*4x+3*4x+3=0
Wy multiply elements
-4x^2+12x+3=0
a = -4; b = 12; c = +3;
Δ = b2-4ac
Δ = 122-4·(-4)·3
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-8\sqrt{3}}{2*-4}=\frac{-12-8\sqrt{3}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+8\sqrt{3}}{2*-4}=\frac{-12+8\sqrt{3}}{-8} $
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