3=r2+7

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Solution for 3=r2+7 equation: 



3=r2+7

We move all terms to the left:

3-(r2+7)=0

We add all the numbers together, and all the variables

-(+r^2+7)+3=0

We get rid of parentheses

-r^2-7+3=0

We add all the numbers together, and all the variables

-1r^2-4=0

a = -1; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-1)·(-4)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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