3=d-65/7

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Solution for 3=d-65/7 equation: 



3=d-65/7

We move all terms to the left:

3-(d-65/7)=0

We add all the numbers together, and all the variables

-(+d-65/7)+3=0

We get rid of parentheses

-d+3+65/7=0

We multiply all the terms by the denominator


-d*7+65+3*7=0

We add all the numbers together, and all the variables

-d*7+86=0

Wy multiply elements

-7d+86=0

We move all terms containing d to the left, all other terms to the right

-7d=-86

d=-86/-7

d=12+2/7

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