3=7(1x-2)+17

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Solution for 3=7(1x-2)+17 equation: 



3=7(1x-2)+17

We move all terms to the left:

3-(7(1x-2)+17)=0

We add all the numbers together, and all the variables

-(7(x-2)+17)+3=0



We calculate terms in parentheses: -(7(x-2)+17), so:

7(x-2)+17

We multiply parentheses

7x-14+17

We add all the numbers together, and all the variables

7x+3

Back to the equation:

-(7x+3)



We get rid of parentheses

-7x-3+3=0

We add all the numbers together, and all the variables

-7x=0

x=0/-7

x=0

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