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3=5/9b
We move all terms to the left:
3-(5/9b)=0
Domain of the equation: 9b)!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
-(+5/9b)+3=0
We get rid of parentheses
-5/9b+3=0
We multiply all the terms by the denominator
3*9b-5=0
Wy multiply elements
27b-5=0
We move all terms containing b to the left, all other terms to the right
27b=5
b=5/27
b=5/27
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