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3=5/2(3x-2
We move all terms to the left:
3-(5/2(3x-2)=0
Domain of the equation: 2(3x-2)+3!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
2(3x-2)!=-3
x∈R
-(5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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