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3=3(2x-5)-(5x+1)
We move all terms to the left:
3-(3(2x-5)-(5x+1))=0
We calculate terms in parentheses: -(3(2x-5)-(5x+1)), so:We get rid of parentheses
3(2x-5)-(5x+1)
We multiply parentheses
6x-(5x+1)-15
We get rid of parentheses
6x-5x-1-15
We add all the numbers together, and all the variables
x-16
Back to the equation:
-(x-16)
-x+16+3=0
We add all the numbers together, and all the variables
-1x+19=0
We move all terms containing x to the left, all other terms to the right
-x=-19
x=-19/-1
x=+19
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