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3=2x-1/3x+12
We move all terms to the left:
3-(2x-1/3x+12)=0
Domain of the equation: 3x+12)!=0We get rid of parentheses
x∈R
-2x+1/3x-12+3=0
We multiply all the terms by the denominator
-2x*3x-12*3x+3*3x+1=0
Wy multiply elements
-6x^2-36x+9x+1=0
We add all the numbers together, and all the variables
-6x^2-27x+1=0
a = -6; b = -27; c = +1;
Δ = b2-4ac
Δ = -272-4·(-6)·1
Δ = 753
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{753}}{2*-6}=\frac{27-\sqrt{753}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{753}}{2*-6}=\frac{27+\sqrt{753}}{-12} $
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