3=2(r-4)+1

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Solution for 3=2(r-4)+1 equation: 



3=2(r-4)+1

We move all terms to the left:

3-(2(r-4)+1)=0



We calculate terms in parentheses: -(2(r-4)+1), so:

2(r-4)+1

We multiply parentheses

2r-8+1

We add all the numbers together, and all the variables

2r-7

Back to the equation:

-(2r-7)



We get rid of parentheses

-2r+7+3=0

We add all the numbers together, and all the variables

-2r+10=0

We move all terms containing r to the left, all other terms to the right

-2r=-10

r=-10/-2

r=+5

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