3=2(n+-1)+-1

Solution for 3=2(n+-1)+-1 equation:

3=2(n+-1)+-1

We move all terms to the left:

3-(2(n+-1)+-1)=0

We add all the numbers together, and all the variables

-(2(n-1)+-1)+3=0

We use the square of the difference formula

-(2(n-1)-1)+3=0


We calculate terms in parentheses: -(2(n-1)-1), so:

2(n-1)-1

We multiply parentheses

2n-2-1

We add all the numbers together, and all the variables

2n-3

Back to the equation:

-(2n-3)


We get rid of parentheses

-2n+3+3=0

We add all the numbers together, and all the variables

-2n+6=0

We move all terms containing n to the left, all other terms to the right

-2n=-6

n=-6/-2

n=+3