3=1/3(-2+c)

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Solution for 3=1/3(-2+c) equation: 



3=1/3(-2+c)

We move all terms to the left:

3-(1/3(-2+c))=0



Domain of the equation: 3(-2+c))!=0

c∈R



We add all the numbers together, and all the variables

-(1/3(c-2))+3=0

We multiply all the terms by the denominator


-(1+3*3(c-2))=0



We calculate terms in parentheses: -(1+3*3(c-2)), so:

1+3*3(c-2)

determiningTheFunctionDomain
3*3(c-2)+1

Wy multiply elements

9c(c+1

Back to the equation:

-(9c(c+1)





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9c(c+1





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