3=-15-2(c-1)-3c

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Solution for 3=-15-2(c-1)-3c equation:



3=-15-2(c-1)-3c
We move all terms to the left:
3-(-15-2(c-1)-3c)=0
We calculate terms in parentheses: -(-15-2(c-1)-3c), so:
-15-2(c-1)-3c
determiningTheFunctionDomain -2(c-1)-3c-15
We add all the numbers together, and all the variables
-3c-2(c-1)-15
We multiply parentheses
-3c-2c+2-15
We add all the numbers together, and all the variables
-5c-13
Back to the equation:
-(-5c-13)
We get rid of parentheses
5c+13+3=0
We add all the numbers together, and all the variables
5c+16=0
We move all terms containing c to the left, all other terms to the right
5c=-16
c=-16/5
c=-3+1/5

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