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3=-12/5k
We move all terms to the left:
3-(-12/5k)=0
Domain of the equation: 5k)!=0We get rid of parentheses
k!=0/1
k!=0
k∈R
12/5k+3=0
We multiply all the terms by the denominator
3*5k+12=0
Wy multiply elements
15k+12=0
We move all terms containing k to the left, all other terms to the right
15k=-12
k=-12/15
k=-4/5
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