3=-(y-2)-6y=1

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Solution for 3=-(y-2)-6y=1 equation: 



3=-(y-2)-6y=1

We move all terms to the left:

3-(-(y-2)-6y)=0



We calculate terms in parentheses: -(-(y-2)-6y), so:

-(y-2)-6y

We add all the numbers together, and all the variables

-6y-(y-2)

We get rid of parentheses

-6y-y+2

We add all the numbers together, and all the variables

-7y+2

Back to the equation:

-(-7y+2)



We get rid of parentheses

7y-2+3=0

We add all the numbers together, and all the variables

7y+1=0

We move all terms containing y to the left, all other terms to the right

7y=-1

y=-1/7

y=-1/7

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