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3=+3(2t-1)
We move all terms to the left:
3-(+3(2t-1))=0
We calculate terms in parentheses: -(+3(2t-1)), so:We get rid of parentheses
+3(2t-1)
determiningTheFunctionDomain 3(2t-1)
We multiply parentheses
6t-3
Back to the equation:
-(6t-3)
-6t+3+3=0
We add all the numbers together, and all the variables
-6t+6=0
We move all terms containing t to the left, all other terms to the right
-6t=-6
t=-6/-6
t=1
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