3=(c)/(-c+10)

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Solution for 3=(c)/(-c+10) equation: 



3=(c)/(-c+10)

We move all terms to the left:

3-((c)/(-c+10))=0



Domain of the equation: (-c+10))!=0

c∈R



We add all the numbers together, and all the variables

-(c/(-1c+10))+3=0

We multiply all the terms by the denominator


-(c+3*(-1c+10))=0



We calculate terms in parentheses: -(c+3*(-1c+10)), so:

c+3*(-1c+10)

We multiply parentheses

c-3c+30

We add all the numbers together, and all the variables

-2c+30

Back to the equation:

-(-2c+30)



We get rid of parentheses

2c-30=0

We move all terms containing c to the left, all other terms to the right

2c=30

c=30/2

c=15

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