3=(9(3/2))+b

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Solution for 3=(9(3/2))+b equation: 



3=(9(3/2))+b

We move all terms to the left:

3-((9(3/2))+b)=0



Domain of the equation: 2))+b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

-((9(+3/2))+b)+3=0

We multiply all the terms by the denominator


-((9(+3+3*2))+b)=0



We calculate terms in parentheses: -((9(+3+3*2))+b), so:

(9(+3+3*2))+b

determiningTheFunctionDomain
b+(9(+3+3*2))

We add all the numbers together, and all the variables

b+(99)

We add all the numbers together, and all the variables

b+99

Back to the equation:

-(b+99)



We get rid of parentheses

-b-99=0

We add all the numbers together, and all the variables

-1b-99=0

We move all terms containing b to the left, all other terms to the right

-b=99

b=99/-1

b=-99

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