3=(1/5)(4x-20)

Solution for 3=(1/5)(4x-20) equation:

3=(1/5)(4x-20)

We move all terms to the left:

3-((1/5)(4x-20))=0


Domain of the equation: 5)(4x-20))!=0

x∈R


We add all the numbers together, and all the variables

-((+1/5)(4x-20))+3=0

We multiply parentheses ..

-((+4x^2+1/5*-20))+3=0

We multiply all the terms by the denominator


-((+4x^2+1+3*5*-20))=0


We calculate terms in parentheses: -((+4x^2+1+3*5*-20)), so:

(+4x^2+1+3*5*-20)

We get rid of parentheses

4x^2+1-20+3*5*

We add all the numbers together, and all the variables

4x^2

Back to the equation:

-(4x^2)


a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-8}=0$