3=(1/3)(6)+b

Solution for 3=(1/3)(6)+b equation:

3=(1/3)(6)+b

We move all terms to the left:

3-((1/3)(6)+b)=0


Domain of the equation: 3)6+b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

-((+1/3)6+b)+3=0

We multiply all the terms by the denominator


-((+1+3*3)6+b)=0


We calculate terms in parentheses: -((+1+3*3)6+b), so:

(+1+3*3)6+b

determiningTheFunctionDomain
b+(+1+3*3)6

We add all the numbers together, and all the variables

b+106

Back to the equation:

-(b+106)


We get rid of parentheses

-b-106=0

We add all the numbers together, and all the variables

-1b-106=0

We move all terms containing b to the left, all other terms to the right

-b=106

b=106/-1

b=-106