3=(1/2)(x+4)

Solution for 3=(1/2)(x+4) equation:

3=(1/2)(x+4)

We move all terms to the left:

3-((1/2)(x+4))=0


Domain of the equation: 2)(x+4))!=0

x∈R


We add all the numbers together, and all the variables

-((+1/2)(x+4))+3=0

We multiply parentheses ..

-((+x^2+1/2*4))+3=0

We multiply all the terms by the denominator


-((+x^2+1+3*2*4))=0


We calculate terms in parentheses: -((+x^2+1+3*2*4)), so:

(+x^2+1+3*2*4)

We get rid of parentheses

x^2+1+3*2*4

We add all the numbers together, and all the variables

x^2+25

Back to the equation:

-(x^2+25)


We get rid of parentheses

-x^2-25=0

We add all the numbers together, and all the variables

-1x^2-25=0

a = -1; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·(-1)·(-25)
Δ = -100
Delta is less than zero, so there is no solution for the equation