3=(-4/5)(-5)+b

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Solution for 3=(-4/5)(-5)+b equation: 



3=(-4/5)(-5)+b

We move all terms to the left:

3-((-4/5)(-5)+b)=0



Domain of the equation: 5)(-5)+b)!=0

b∈R



We multiply parentheses ..

-(4+b)+3=0

We add all the numbers together, and all the variables

-(b+4)+3=0

We get rid of parentheses

-b-4+3=0

We add all the numbers together, and all the variables

-1b-1=0

We move all terms containing b to the left, all other terms to the right

-b=1

b=1/-1

b=-1

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