39=2x-5(-16+3)

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Solution for 39=2x-5(-16+3) equation: 



39=2x-5(-16+3)

We move all terms to the left:

39-(2x-5(-16+3))=0

We add all the numbers together, and all the variables

-(2x-5(-13))+39=0



We calculate terms in parentheses: -(2x-5(-13)), so:

2x-5(-13)

We add all the numbers together, and all the variables

2x+65

Back to the equation:

-(2x+65)



We get rid of parentheses

-2x-65+39=0

We add all the numbers together, and all the variables

-2x-26=0

We move all terms containing x to the left, all other terms to the right

-2x=26

x=26/-2

x=-13

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