390=2(2/3x)+2(x)

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Solution for 390=2(2/3x)+2(x) equation: 



390=2(2/3x)+2(x)

We move all terms to the left:

390-(2(2/3x)+2(x))=0



Domain of the equation: 3x)+2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(2(+2/3x)+2x)+390=0

We multiply all the terms by the denominator


-(2(+2+390*3x)+2x)=0



We calculate terms in parentheses: -(2(+2+390*3x)+2x), so:

2(+2+390*3x)+2x

We add all the numbers together, and all the variables

2(390*3x+2)+2x

We add all the numbers together, and all the variables

2x+2(390*3x+2)

We multiply parentheses

2x+2340x+4

We add all the numbers together, and all the variables

2342x+4

Back to the equation:

-(2342x+4)



We get rid of parentheses

-2342x-4=0

We move all terms containing x to the left, all other terms to the right

-2342x=4

x=4/-2342

x=-2/1171

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