39-3(z+1)=3z

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Solution for 39-3(z+1)=3z equation: 



39-3(z+1)=3z

We move all terms to the left:

39-3(z+1)-(3z)=0

We add all the numbers together, and all the variables

-3z-3(z+1)+39=0

We multiply parentheses

-3z-3z-3+39=0

We add all the numbers together, and all the variables

-6z+36=0

We move all terms containing z to the left, all other terms to the right

-6z=-36

z=-36/-6

z=+6

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