39-(2x+8)=2(x+3)+x

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Solution for 39-(2x+8)=2(x+3)+x equation: 



39-(2x+8)=2(x+3)+x

We move all terms to the left:

39-(2x+8)-(2(x+3)+x)=0

We get rid of parentheses

-2x-(2(x+3)+x)-8+39=0



We calculate terms in parentheses: -(2(x+3)+x), so:

2(x+3)+x

We add all the numbers together, and all the variables

x+2(x+3)

We multiply parentheses

x+2x+6

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

-2x-(3x+6)+31=0

We get rid of parentheses

-2x-3x-6+31=0

We add all the numbers together, and all the variables

-5x+25=0

We move all terms containing x to the left, all other terms to the right

-5x=-25

x=-25/-5

x=+5

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